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When an AC signal of frequency 1 kHz is ...

When an `AC` signal of frequency `1 kHz` is applied across a coil of resistance `100 Omega`, then the applied voltage leads the current by `45^@`. The inductance of the coil is

A

`16 mH`

B

`12mH`

C

`8mH`

D

`4mH`

Text Solution

Verified by Experts

The correct Answer is:
A

`45^@` phase angle means
`X_L=R`
`:. (2pifL)=R`
`:. L=R/(2pif)`
`=100/((2pi)(10^3))`
`=0.0159H`
`=16mH`
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