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In the AC network shown in figureure the...

In the `AC` network shown in figureure the rms current flowing through the inductor and capacitor are `0.6 A` and `0.8A`, respectively. Then the current coming out of the source is
.

A

`1.0A`

B

`1.4A`

C

`0.2A`

D

none of the above

Text Solution

Verified by Experts

The correct Answer is:
C
`I_C` is `90^@` a head of the applied votage and `I_L` lags behind the applied voltage by `90^@`. So, there is a phase difference of `180^@` between `I_L and I_C`.
`:. I=I_C=I_L=0.2A`
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