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In series L-C-R circuit, voltage drop ac...

In series `L-C-R` circuit, voltage drop across resistance is `8V`, across inductor is `6V` and across capacitor is `12V`. Then,

A

voltage of the source will be leading in the circuit

B

voltage drop across each element will be less than the applied voltage

C

power factor of the circuit will be `3/4`

D

none of the above

Text Solution

Verified by Experts

The correct Answer is:
D
`V=sqrt(V_R^2+(V_C-V_L)^(2))i=10V`
`V_CgtV_L` hence current leads the voltage.

Power factor `=cosphi=8/10=0.8`
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