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An AC voltage source described by V=10co...

An AC voltage source described by `V=10cos(pi/2)t` is connected to a `1muF` capacitor as shown in figureure. The key `K` is closed at `t=0`. the time `(tgt0)` after which the magntitude of current `I` reaches its maximum value for the first time is
.

A

`1s`

B

`2s`

C

`3s`

D

`4s`

Text Solution

Verified by Experts

The correct Answer is:
A
Current will lead the voltage function by `90^@` voltage function is cos function. Therefore current function will be `-sin` function

`t_0=T/4=((2pi/omega))/4=pi/(2omega)`
`=pi/(2(pi/2))=1s`.
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