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In the circuit shown in figureure, ....

In the circuit shown in figureure,
.

A

`V_R=80V`

B

`X_C=50Omega`

C

`V_L=40V`

D

`V_0=100V`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

(a) `V_R=IR=80V`
(b) `X_C=V_C/I=100/2=50Omega`
(c) `V_L=IX_L=40V`
(d) `V=V_(rms)=sqrt(V_R^2+(V_C-V_L)^2)`
`=sqrt((80)^2+(100-40)^2)`
`=60V`
`:. V_0=sqrt(2)V_("rms")=60sqrt(2)V`
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