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A point object is placed at equal distan...

A point object is placed at equal distance 3 f in front of a concave mirror, a convex mirror and plane mirror separately (event-1). Now, the distance is decreased to 1.5 f from all the three mirror (event-2). Magnitude of focal length of convex mirror and concave mirror is f . Then choose the correct options.

A

Maximum distance of object in event-1 from the mirror is from plane mirror

B

Minimum distanc of object in event-1 from the mirrro is from convex mirror.

C

Maximum distance of object in event-2 from the mirror is from concave mirror

D

Minimum distance of object in event-2 from the mirror is from plane mirrror

Text Solution

Verified by Experts

The correct Answer is:
A

In event-1
for concave mirror, `1/v+1/(-3f)=1/(-f)`
`:. v=-1.5f`
for convex mirror
`1/v+1/(-3f)=1/(+f)`
`:. v=(3/4)f=-0.75f`
for plane mirror,
`v = +3f`
In event-2
For concave mirror, `1/v+1/(-1.5f)=1/(-f)`
`:. v=-3f`
for convex mirror
`1/v+1/(-1.5f)=1/+f)`
`:. v=(3f)/(5)=-0.6f`
for plane mirror,
`v = +1.5f`.
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