A ray of light passes through two slabs of same thickness. In the first slab `n_(1)` waves are formed and in the second slab `n_2`. Find refractive `
` index of second medium with respect to first.

Answer

A, B

Explanation

One wave means one wavelength . So, if t is the thickness of slab, `lambda` the wavelength
and `n` the number of waves, then
`nlambda=t rArr lambda =t/n `
or `lambda prop (1)/(n)` (as `t` is same) or `(lambda_(1))/(lambda_(2) )= (n_(2))/(n_(1)) `
Now refractive, index of second medium `w.r.t.` first medium is
`._(1)mu_(2) = (lambda_(1))/(lambda_(2)) = (n_(2))/(n_(1))`