In Fig, find position of second image `I_2` formed after two times refraction from two place surfaces AB and CD.

Explanation

We will apply `v=mu_2/mu_1 u`, two times with using the fact that object and image are on same side of the surface.
Refraction from AB
` mu_1=1 `
` mu_2=1.5 `
` u=EO=10cm` (towards left of AB)
` v=(mu_2/mu_1)u=1.5/1 (10) `
or `v=EI_1=15cm` (towards left of AB)
Refraction from CD `I_1` will act as an object for refraction from CD
` mu_1=1.5` and `mu_2=2 `
` u=FI_1=FE+EI_(1)=(10+15)`
` =25cm` (towards left of CD)
` v=(mu_2/mu_1) (u)=(2/1.5)(25) `
` =100/3` cm (towards left of CD)
` =FI_2 `
The correct figure is as shown below