Home
Class 12
PHYSICS
A diverging lens is made of material wit...

A diverging lens is made of material with refractive index `1.3` and has identical concaves surfaces of radius `20 cm.` The lens is immersed in a transparent medium with refractive index `1.8.`
(a) What is now the focal length of the lens?
(b) What is the minimum distance taht an immersed object must be from the lens so that a real image is formed?

Text Solution

Verified by Experts

The correct Answer is:
A, B, C

(a) `1/f=(1.3/1.8-1)(1/(-20)-1/(+20))`
`:. f=+36 cm`
(b) Between O and `F_1` image is virtual. Hence, for
real image.
`|mu|ltf` or `36 cm`
Promotional Banner

Topper's Solved these Questions

  • REFRACTION OF LIGHT

    DC PANDEY|Exercise Exercise 31.7|2 Videos
  • REFRACTION OF LIGHT

    DC PANDEY|Exercise Exercise 31.8|8 Videos
  • REFRACTION OF LIGHT

    DC PANDEY|Exercise Exercise 31.5|5 Videos
  • REFLECTION OF LIGHT

    DC PANDEY|Exercise Subjective|9 Videos
  • SEMICONDUCTORS

    DC PANDEY|Exercise Subjective|12 Videos

Similar Questions

Explore conceptually related problems

A thin lens made of a material of refractive index mu_(0) has a focal length f_(0) in air. Find the focal length of this lens if it is immersed in a liquid of refractive index mu .

A plano-convex lens has refractive index 1.6 and radius of curvature 60 cm. What is the focal length of the lens?

A thin converging lens made of glass of refractive index 1.5 acts as a concave lens of focal length 50 cm , when immersed in a liquid of refractive index 15//8 . Calculate the focal length of converging lens in air.

A converging lens of refractive index 1.5 is kept in a liquid medium having the same refractive index. What would be the focal length of the lens in the medium ?

A diverging lens of refractive index 1.5 and focal length 15 cm in air has same radii of curvature for both sides. If it is immersed in a liquid of refractive index 1.7 , calculate focal length of the lens in liquid.

A convex lens of focal length 20 cm made of glass of refractive index 1.5 is immersed in water having refractive index 1.33 . The change in the focal length of lens is

A converging lens of refractive index 1.5 and of focal length 15 cm in air, has the same radii of curvature for both sides. If it is immersed in a liquid of refractive index 1.7 , find the focal length of the lens in the liquid.