Light is incident from glass `(mu_g=3/2)` to water `(mu_w=4/3).` Find the range of the angle of deviat on for refracted light.

Answer

A, C

Explanation

`theta_C=sin^-1(mu_R/mu_D)=sin^-1((4//3)/(3//2))=sin^-1(8//9)`


`:. delta_1=0^@ :. delta_2=90^@-theta_C`
`cos delta_2=cos(90^@-theta_C)=sin theta_C=8/9`
`:. delta_2=cos^-1(8/9)`