Two slits spaced 0.450nm apart are placed 75.0 cm from a screen. What is the distance between the second and third dark lines of the interference pattern on the screen when the slits are illuminated with coherent light with a wavelength of 500nm?

Explanation

The required distance= one fringe width
`=omega = (lambdaD)/d`
` = ((500 xx 10^(-9))(0.75))/(0.45 xx (10^-3)) `
` = 8.33 xx 10^-4`
= 0.83mm.