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The energy of a photon is equal to the k...

The energy of a photon is equal to the kinetic energy of a
proton. The energy of the photon is E. Let `lambda_1`be the de-Broglie wavelength of the
proton and `lambda_2` be the wavelength of the photon. The ratio `(lambda_1)/(lambda_2)` is proportional to
(a)`E^0` (b) `E^(1//2)` (c ) `E^(-1)` (d)`E^(-2)`

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The correct Answer is:
To solve the problem, we need to find the ratio of the de Broglie wavelength of a proton (\( \lambda_1 \)) to the wavelength of a photon (\( \lambda_2 \)) when the energy of the photon is equal to the kinetic energy of the proton. ### Step 1: Determine the de Broglie wavelength of the proton (\( \lambda_1 \)) The de Broglie wavelength of a particle is given by the formula: \[ \lambda_1 = \frac{h}{p} \] where \( h \) is Planck's constant and \( p \) is the momentum of the proton. ### Step 2: Express the momentum of the proton in terms of kinetic energy The momentum \( p \) of the proton can be expressed in terms of its kinetic energy \( E \): \[ p = \sqrt{2mE} \] where \( m \) is the mass of the proton and \( E \) is its kinetic energy. Since the energy of the photon is equal to the kinetic energy of the proton, we can use \( E \) for both. ### Step 3: Substitute the momentum into the de Broglie wavelength formula Now substituting the expression for momentum into the de Broglie wavelength formula: \[ \lambda_1 = \frac{h}{\sqrt{2mE}} \] ### Step 4: Determine the wavelength of the photon (\( \lambda_2 \)) The wavelength of a photon is related to its energy by the equation: \[ \lambda_2 = \frac{hc}{E} \] where \( c \) is the speed of light. ### Step 5: Find the ratio \( \frac{\lambda_1}{\lambda_2} \) Now we can find the ratio of the two wavelengths: \[ \frac{\lambda_1}{\lambda_2} = \frac{\frac{h}{\sqrt{2mE}}}{\frac{hc}{E}} = \frac{h \cdot E}{\sqrt{2mE} \cdot hc} \] This simplifies to: \[ \frac{\lambda_1}{\lambda_2} = \frac{E}{\sqrt{2mE} \cdot c} \] ### Step 6: Simplify the expression We can further simplify this expression: \[ \frac{\lambda_1}{\lambda_2} = \frac{E^{1/2}}{\sqrt{2m} \cdot c} \] ### Conclusion: Determine the proportionality From the final expression, we can see that the ratio \( \frac{\lambda_1}{\lambda_2} \) is proportional to \( E^{1/2} \). Thus, the correct answer is: **(b) \( E^{1/2} \)**

To solve the problem, we need to find the ratio of the de Broglie wavelength of a proton (\( \lambda_1 \)) to the wavelength of a photon (\( \lambda_2 \)) when the energy of the photon is equal to the kinetic energy of the proton. ### Step 1: Determine the de Broglie wavelength of the proton (\( \lambda_1 \)) The de Broglie wavelength of a particle is given by the formula: \[ \lambda_1 = \frac{h}{p} ...
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