An `alpha`- particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are `lambda_a`
and `lambda_p` respectively. The ratio `(lambda_p)/(lambda_a)`, to the nearest integer, is.

Answer

A, C

Explanation

`:. lambda =(h)/(p) = (h)/(sqrt2qVm
or `lambda prop(1)/(sqrtqm`
`(lambda_p)/lambda_a) = sqrt((qa)/(qp). (m_a)/(m_p))`
= `sqrt((2)(4))/((1)(1)) =2.828`
. The nearest integer is 3. :.Answer is 3.