Find the kinetic energy, potential energy and total energy in
first and second orbit of hydrogen atom if potential energy in first orbit is taken
to be zero.

Answer

B

Explanation

`E_1 = - 13.60eV`, `k_1 =-E_1 =13.60`, `U_1 = 2E_1 = 27.20eV`
`E_2 = (E_1)/((2))^2 =- 3.40, K_2 = 3.40eV` and E_2 =- 6.80eV`
Now, `U_1 = 0`, i.e. potential energy has benn increased by 27.20eV. So, we will increase U and E
in all energy states by 27.20eV. while kinetic energy will remain unchanged. Changed values in
tabular form are us under.