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Find de-Broglie wavelength of single ele...

Find de-Broglie wavelength of single electron in 2 nd orbit of hydrogen atom by two methods.

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The correct Answer is:
D
Kinetic energy of single electron in 2nd orbit is 3.4 eV using the equation, `lambda = sqrt(150)/(KE(in eV) = sqrt(150)/(3.4) = 6.64 Å`
Circumference of nth orbit = n`lambda`
:. 2pir=2lambda`
or `lambda = pi r `
Now, `r prop n^2`
`r_1 = pi (0.529)(2)^2 Å`
`=6.64 Å`
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