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What will be the maximum kinetic energy of the photoelectrons ejected from magnesium (for which the work -function W=3.7 eV) when irradiated by ultraviolet light of frequency `1.5xx10^15 s^(-1)`.

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The correct Answer is:
A, B
`E = hf=((6.63xx10^(-34)(1.5 xx10^(15)))/(1.6 xx10^(-19)`
`K_(max) = E - W = 6.21 - 3.7 = 2.51 eV.
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