Let `A_(0)` be the area enclined by the orbit in a hydrogen atom .The graph of in `(A_(0) //A_(1))` against `ln(n)`

Options

A. Will not pass through origin
B. Will be a straight line with slope 4
C. will be rectangular hyperbola
D. Will be parabola

Answer

B

Explanation

`A = pir^2`
`A prop r^2 or A prop n^4 (as r prop n^2)`
`:. (A_n)/(A_1) = ((n))^4`
`in ((A_n)/(A_1)) = 4 in (n)`
Therefore, in ((A_n)/(A_1)) versus in n graph is a straight
line of slop 4.