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Light wave described by the equation 2...

Light wave described by the equation `200 V//m sin (1.5xx10^15 s^(-1) t cos (0.5xx10^15 s^(-1) t` falls metal surface having work function 2.0 eV. Then, the maximum kinetic energy photoelectrons is

A

`3.27eV`

B

`2.2eV`

C

`2.85eV`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
`omega_(max) = 1.5xx10^(15) rad/s = 2pif_(max)`
`:. f_(max) = (1.5xx10)^15/(2pi) Hz`
`E = (hf_(max)/(1.6xx10^(-19) eV`
`=(6.63xx10^(-34)xx1.5xx10^(15)/(2pixx1.6xx10^(-19) eV`
`~~1.0 eV`
Since, E lt W, no photoemission can take place.
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