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A stationary nucleus of mass 24 amu emit...

A stationary nucleus of mass 24 amu emits a gamma photon. The energy of the emitted photon is 7 MeV. The recoil energy of the nucleus is

A

(a) `2.2keV`

B

(b) `1.1 keV`

C

(c) `3.1 keV`

D

(d) `2.2 keV`

Text Solution

Verified by Experts

The correct Answer is:
B
From momentum of conservation, momentum of photon=photon of nucleus
`:.` `E/c=sqrt(2Km)`
`:.` `K=(E^2)/(2mc^2)`
`=((7xx1.6xx10^-13)^2)/(2xx24xx1.67xx10^-27xx(3xx10^8)^2xx1.6xx10^-16)keV`
`=1.1keV`
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