The heat produced in a long wire is characterised by resistance , current and time through which the current passes. If the errors in measuring these quantities are respectively 1%, 2% and 1% then total error in calculating the energy produced is

Options

A. `4%`
B. `6%`
C. `4//3%`
D. `8%`

Answer

B

Explanation

The heat produced in a wire due to current flow is given by
`H=l^(2)Rt`
`therefore (DeltaH)/(H)=(2DeltaI)/(I)+(DeltaR)/(R)+(Deltat)/(t)`
`=2xx0.2 +0.01+0.01=0.06 =6%`