The ion which is not tetrahedral in shape is

Options

A. `BF_4^-`
B. `NH_4^+`
C. `Cu(NH_3)_4^(2+)`
D. `NiCl_4^(2-)`

Answer

C

Explanation

`[Cu(NH_3)_4]^(2+)`
`Cu^(2+) to 3d^(9) 4s^0`

One electron is shifted from 3d to 4p orbital.