Time required to deposit one milli"mole" of aluminium metal by the passage of 9.65 amp through aqueous solution of aluminium ion is:

Options

A. 30s
B. 10s
C. 30,000 s
D. 10,000 s

Answer

B

Explanation

`Al^(3+) + 3e^(-) to Al`
For deposition of 1g equivalent `-=` 96500 C
For deposition of 1 millimole `-=` 96.500 C
As Q = It `rArr t=Q/I = (96.5)/(9.65) = 10s.`