The moment of inertia of a rod about an axis through its centre and perpendicular to it, is `(1)/(12)ML^(2)` (where, M is the mass and L is length of the rod). The rod is bent in the middle, so that two halves make an angle of `60^(@)`. The moment of inertia of the bent rod about the same axis would be

Options

A. `(1)/(48)ML^(2)`
B. `(1)/(12)ML^(2)`
C. `(1)/(24)ML^(2)`
D. `(ML^(2))/(8sqrt(3))`

Answer

B

Explanation

Moment of inetia of unifcrm road about one end `=(ML^(2))/(3)`

`:.` Moment of inertia of a rod about an axis passing through O and perpendicular to the plane of the road will be. `=2((M)/(2))((L//2)^(2))/(3)=(ML^(2))/(4xx3)=(ML)/(12)`