The fossil bone has a `.^(14)C` : `.^(12)C` ratio, which is `[(1)/(16)]` of that in a living animal bone. If the half -life of `.^(14)C` is `5730` years, then the age of the fossil bone is :

Options

A. 11460 years
B. 17190 years
C. 22920 years
D. 45840 years

Answer

C

Explanation

After 5730, years, the number of `C^(14)` remaining is `(1)/(2)th` original. The have (1/16) original value,it takes `(1//2)^(4)` , half lives.
Therefore, the bone is `4xx5730` years `=22920` years old.