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In [Ag(CN)2]^(-), the number of pi bonds...

In `[Ag(CN)_2]^(-)`, the number of `pi` bonds is

A

2

B

3

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
c

Cyanide is connsidered, in a brod sense, to be the most potent ligand for many transition metals.
The very high affinites of metals for cyanide can be attributed to its negative charge, compactness and ability to engage in `pi` bonding.
The dicyanides `[M(CN)_(2)]^(-)(M=Cu,AgAu)` are `-Coverset(1 sigma)underset(2pi)(-=)N-` Thus, two cyanide ions have `4pi` bonds.
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