The major product formed in the following reaction is `CH_(3)CH(Cl)CH_(2)-CH_(2)OHoverset(aq.KOH)to`

Options

A. `CH_(3)CH=CH-CH_(2)OH`
B. `CH_(2)=CH-CH_(2)-CH_(2)OH`
C. `{:(CH_(3)-CH-CH_(2)),(" | |"),(" "O-CH_(2)):}`
D. `CH_(3)-underset(OH)underset(|)CH-CH_(2)-CH_(2)OH`

Answer

d

Explanation

Halogenated compounds on tratement with aq. KOH form alcohols. The halgen atom is subsituted by -OH group.
`CH_(3)CH(CI)CH_(2)-CH_(2)OH overset("aq.KOH") to CH_(3)CH(OH)CH_(2)-CH_(2)OH`
Here `OH^(-)` acts as a nucleophile.