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Side of an equilateral triangle is I . Three point masses, each of magnitude m, are palced at the three vertices of the triangle . Momment of inertia of this system about one side of the triangle as axis is given by

A

`(3ml^2)/4`

B

`4/3 mt^2`

C

`3/2 ml^2`

D

`2/3 ml^2`

Text Solution

Verified by Experts

The correct Answer is:
A

Distance of corner mass from opposite side = r
`r^(2) = l^(2) - ((l)/(2))^(2) = (3l^(2))/(4)`
`l = mr^(2) = (3)/(4) ml^(2)`
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