A converging lens forms a real image `I` on its optic axis. A rectangular galss slab of refractive index `mu` and thickness `t` is introduced between the lens and `I`. `I` will move

Options

A. towards the lens ` (mu-1)x `
B. towards the lens by `(1-1/mu)x `
C. anway from the lens by `(mu- 1)`
D. away from the lens by `(1-1/mu )x `

Answer

D

Explanation

Due to insertion of slab , the optical path increases by `x//mu` , where x is thickness of slab .
Therefore the converging point will shift away by `[x - (x)/(mu)] = x(1 - (1)/(mu))`.