A bulb of 25 W , 200 V and another bulb of 100 W 200 V are connected in series with a supply line of 220 V. Then

Options

A. both bulbs will glow with same brightness
B. both bulbs will get fused
C. 25 W bulb will glow more brightly
D. 100 W bulb will glow more brightly.

Answer

C

Explanation

Resistance of 25 W , 200 V bulb
`R_(1) = ((200)^(2))/(25) Omega`
Resistance of 100 W , 200 V bulb
`R_(2) = ((200)^(2))/(100) Omega`.
Clearly , `R_(1) gt R_(2) , therefore H_(1) gt H_(2)`
`therefore ` 25 W bulb will glow more brightly .