The current curve between `log_e""(j)/(T^2)" and "l/T`

Options

A.
B.
C.
D.

Answer

A

Explanation

We know that `J = AT^(2) e^(-h//T)`
`(J)/(T^(2)) = Ae^(-h//T)`
Taking log both side , we get
`log _(e) (J)/(T^(2)) = log _(e) (A * e^(-h//T))`
`log_(e) (J)/(T^(2)) = log_(e) A - (b)/(T)`
Comparing with y = mx + C
we get correct option is (a) .