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CH3CH=CHCH3+CHCl3+t-BuOK rarr A.A...

`CH_3CH=CHCH_3+CHCl_3+t-BuOK rarr A.A`

A

B

C

`CH_3underset(OBu)underset(|)"CH"-underset(Cl)underset(|)CHCH_3`

D

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Verified by Experts

The correct Answer is:
B
It is a method of preparation of cycloalkanes .
`CH_(3) - CH = CH - CH_(3) + CHCl_(3) overset((CH_(3))_(3) C-OK)(to)`
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