An N-P-N transistor is connécted in common emitter contiguration in which collector supply is 9V and the voltage drop across the load resistance of `1000Omega` connected in the collector circuit is 1V. If current amplification factor is (25/26), If the internal following options is incorrect.

Explanation

The circuit arrangement is shown in figure. Collector currnet `I_(C)=("Voltage drop across R"_(1))/(R_(1))`
`=(1)/(1000)=10^-3"amp"`
Now, vc `V_(CE)=9-1=8"volt"`
`=(l_(C))/(l_(B))" "(25)/(26)=(10^(-3))/(I_B)`
Current gain `beta= or `
`therefore I_(B)=1.04xx10^(-3)amp`