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In a series LR circuit (L=3H,R=1.5Omega)...

In a series `LR` circuit `(L=3H,R=1.5Omega)` and `DC` voltage `=1V`. Find current at `T=2` seconds.

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`I=(epsi)/(R)[1-e^(-t//c)]`
`tau=L/R" "I=(1)/(1.5)[1-e^((-2)/(2))]`
`tau=(3)/(1.5)=2" "I=(2)/(3)[1-(1)/(e)]=0.4Amp`
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