A bucket tied at the end of a `1.6m` long string is whirled in a verticle circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill, when the bucket is at the highest position `(Takeg=10m//s^(2))`

Options

A. `4m//sec`
B. `6.25m // sec`
C. `16m// sec`
D. None of the above

Answer

A

Explanation

Since water does not fall down, therefore the velocity of revolution should be just sufficienttoprovidecentripetalacceleration atthetopofvertical circle.So,
`v = sqrt((gr)) = sqrt({10 xx (1.6)}) = sqrt((16)) = 4 m//sec`