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The ratio of the longest to shortest wav...

The ratio of the longest to shortest wavelength in Brackett series of hydrogen spectra is

A

`(25)/(9)`

B

`(17)/(6)`

C

`(9)/(5) `

D

`(4)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A

For Bracket series
`(1)/(lambda_(max))=R[(1)/(4^(2))-(1)/(5^(2))] = (9)/(25 xx 16)R`
and `(1)/(lambda_(min)) = R[(1)/(4^(2))-(1)/(oo^(2))] =(R)/(16) rArr (lambda_(max))/(lambda_(min)) =(25)/(9)`
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