A proton is projected with velocity `vecV=2hati` in a regionn where magnetic field `vecB=(hati+3hatj+4hatk)muT` and electric field `vecE=10hatimuV//m`. Then find out the net acceleration of proton:

Options

A. `1400m//s^(2)`
B. `700m//s^(2)`
C. `1000m//s^(2)`
D. `800m//s^(2)`

Answer

A

Explanation

`vecF=QvecE+Q(vecVxxvecB)`
`vecF=1.6xx10^(-19)xx10hatixx10^(-6)+1.6xx10^(-19)[(2hati)xx(hati+3hatj+4hatk)]xx10^(-6)`
`vecF=1.6xx10^(-19)[10hati+6hatk-8hatj]xx10^(-6)`
`vecF=1.6xx10^(-19)[10hati-8hatj+6hatk]xx10^(-6)N`
`veca=1.6xx10^(-19)[10hati-8hatj+6hatk]xx10^(-6)//1.6xx10^(-27)m//s^(2)`
`=1400m//s^(2)`