Find total energy, `PE & KE` of electron in :
(A) `2^(nd)` orbit of `He^(+)` ion.
(B) `1^(st)` excited state of `Be^(+3)` ion.

Options

A. `-10.6eV`
B. `-13.6eV`
C. `-15.6eV`
D. `-25.6eV`

Answer

C

Explanation

`E=-13.6eV(z^(2))/(n^(2))`
`=-13.6eV(z^(2))/(z^(2))=-13.6eV`