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The temperature of food material in refr...

The temperature of food material in refrigerator is `4^(@)C` and temperature of environment is `15^(@)C`. If carnot cycle is used in its working gas, then find its carnot efficiency.

A

a.0.038

B

b.0.028

C

c.0.053

D

d.0.072

Text Solution

Verified by Experts

The correct Answer is:
A
`eta=1-(T_(2))/(T_(1))`
`=1-(273+4)/(273+15)`
`=0.038`
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