निम्नलिखित में सत्यापित कीजिए कि `A(adjA)=(adjA).A=|A|.I` है।
`[(2,3),(-4,-6)]`

Explanation

`A=[(2,3),(-4,-6)]`
`A_(11)=(-1)^(1+1)(-6)=-6`
`A_(12)=(-1)^(1+2)(-4)=4`
`A_(21)=(-1)^(2+1)3=-3`
`A_(22)=(-1)^(2+2)2=2`
`:.adjA=[(6,4),(-3,2)]'=[(-6,-3),(4,2)]`
अब `|A|=|(2,3),(-4,-6)|=-12+12=0`
`A.(adjA)=[(2,3),(-4,-6)][(-6,-3),(4,2)]`
`=[(-12+12,-6+6),(24-24,12-12)]`
`=[(0,0),(0,0)]=0`
`(adjA).A=[(-6,-3),(4,2)][(2,3),(-4,-6)]`
`=[(-12+12,-18+18),(8-8,12-12)]`
`=[(0,0),(0,0)]=0`
`|A|.I=0xxI=0`
`:.A.(adjA)=(adjA).A=|A|.I`