`y'=(x+y)/(x)`

Explanation

`(dy)/(dx)=(x+y)/(x)`
`implies v+x(dv)/(dx)=(x+vx)/(x)=1+v`
माना y=vx `implies (dy)/(dx)=v+x(dv)/(dx)`
`implies x(dv)/(dx)=1 implies dv=(dx)/(x)`
`implies intdv=int(dx)/(x)+c implies v=logx+c`
`implies (y)/(x)=logx+c`
`implies y = x log x + cx`