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x^(2)(dy)/(dx)=x^(2)-2y^(2)+xy...

`x^(2)(dy)/(dx)=x^(2)-2y^(2)+xy`

लिखित उत्तर

Verified by Experts

`x^(2)dy-(x^(2)+xy-2y^(2))dx=0`
`implies (dy)/(dx)=(x^(2)+xy-2y^(2))/(x^(2))`
`implies v+x(dv)/(dx)=(x^(2)+x^(2)v-2x^(2)v^(2))/(x^(2))`
`=1+v-2v^(2)`
`implies x(dv)/(dx)=1-2v^(2)`
माना `y = vx implies (dy)/(dx)=v+x(dv)/(dx)`
`implies (dv)/(1-2v^(2))=(dx)/(x)`
`implies (1)/(2)int(1)/(((1)/sqrt(2))^(2)-v^(2))dv=int(dx)/(x)+c`
`=(1)/(2).(1)/(2.(1)/(sqrt(2)))log.((1)/(sqrt(2))+v)/((1)/(sqrt(2))-v)=logx+c`
`implies (1)/(2sqrt(2))log.(1+vsqrt(2))/(1-vsqrt(2))=logx+c`
`implies (1)/(2sqrt(2))log.(1+(y)/(x)sqrt(2))/(1-(y)/(x)sqrt(2))=log x+c`
`implies (1)/(2sqrt(2))log.(x+ysqrt(2))/(x-ysqrt(2))=logx+c`
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