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Number of ways in which 12 different thi...

Number of ways in which 12 different things can be divided among five persons so that they can get 2,2,2,3,3 things respectively is

A

`(12!)/((3!)^(2)(2!)^(3))`

B

`(12!5!)/((3!)^(2)(2!)^(3))`

C

`(12!)/((3!)^(2)(2!)^(4))`

D

`(12!5!)/((3!)^(2)(2!)^(4))`

Text Solution

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The correct Answer is:
To solve the problem of distributing 12 different things among 5 persons such that they receive 2, 2, 2, 3, and 3 items respectively, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the total items and their distribution**: We have 12 different items and we need to distribute them among 5 persons such that three persons receive 2 items each and two persons receive 3 items each. 2. **Calculate the total arrangements of items**: Since all 12 items are different, the total number of ways to arrange these items is given by \(12!\) (12 factorial). \[ \text{Total arrangements} = 12! \] 3. **Account for identical distributions**: Since three persons receive 2 items each, we need to divide by the arrangements of these identical distributions. The number of ways to arrange 3 persons receiving 2 items each is given by \(3!\) (3 factorial) because they are indistinguishable in terms of the number of items they receive. \[ \text{Ways for 2 items} = 3! = 6 \] 4. **Account for the other identical distributions**: Similarly, for the two persons who receive 3 items each, we also need to divide by \(2!\) (2 factorial) because they are indistinguishable as well. \[ \text{Ways for 3 items} = 2! = 2 \] 5. **Combine the calculations**: Now, we combine these calculations to find the total number of ways to distribute the items. \[ \text{Total ways} = \frac{12!}{(2!)^3 \times (3!)^2} \] Here, \((2!)^3\) accounts for the three persons receiving 2 items each, and \((3!)^2\) accounts for the two persons receiving 3 items each. 6. **Final expression**: Thus, the final expression for the number of ways to distribute the items is: \[ \text{Total ways} = \frac{12!}{2^3 \times 3^2} \] ### Final Calculation: - Calculate \(12!\), \(2^3\), and \(3^2\): - \(12! = 479001600\) - \(2^3 = 8\) - \(3^2 = 9\) - Now substitute these values into the expression: \[ \text{Total ways} = \frac{479001600}{8 \times 9} = \frac{479001600}{72} = 6652800 \] ### Conclusion: The total number of ways to distribute the 12 different items among the 5 persons such that they receive 2, 2, 2, 3, and 3 items respectively is **6652800**.
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