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There are 12 points in a plane in which ...

There are 12 points in a plane in which 6 are collinear. Number of different straight lines that can be drawn by joining them, is

A

51

B

52

C

132

D

18

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The correct Answer is:
To solve the problem of finding the number of different straight lines that can be drawn by joining 12 points in a plane, where 6 of these points are collinear, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Total Points**: We have a total of 12 points in the plane. 2. **Choosing Points to Form Lines**: A straight line can be formed by joining any two points. The number of ways to choose 2 points from 12 can be calculated using the combination formula: \[ \text{Total lines} = \binom{12}{2} = \frac{12 \times 11}{2} = 66 \] 3. **Accounting for Collinear Points**: Among the 12 points, 6 points are collinear. This means that if we choose any 2 points from these 6, they will not form distinct lines since they all lie on the same line. The number of ways to choose 2 points from these 6 collinear points is: \[ \text{Collinear lines} = \binom{6}{2} = \frac{6 \times 5}{2} = 15 \] 4. **Adjusting for the Collinear Points**: Since all 6 collinear points form only one line, we need to subtract the number of lines formed by choosing 2 points from these 6 from our total. However, we need to add back 1 because all 6 points together form a single line. Thus, the adjustment is: \[ \text{Distinct lines} = \text{Total lines} - \text{Collinear lines} + 1 \] Plugging in the values: \[ \text{Distinct lines} = 66 - 15 + 1 = 52 \] 5. **Final Answer**: Therefore, the total number of different straight lines that can be drawn by joining the 12 points is: \[ \boxed{52} \]
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ARIHANT MATHS-PERMUTATIONS AND COMBINATIONS -Exercise For Session 6
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