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Let p=2520, x=number of divisors of p wh...

Let p=2520, x=number of divisors of p which are multiple of 6, y=number of divisors of p which are multiple of 9, then

A

x=12

B

x=24

C

y=12

D

y=16

Text Solution

Verified by Experts

The correct Answer is:
B, D
`becausep=2520=2^(3)*3^(2)*5^(1)*7^(1)`
`=6*2^(2)*3^(1)*5^(1)*7^(1)=9*2^(3)*5^(1)*7^(1)`
`thereforex=(2+1)(1+1)(1+1)(1+1)=24`
and `y=(3+1)(1+1)(1+1)=16`.
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