Balance the following reaction in acidic medium.
`CuS+NO_(3)^(ө)rarrcu^(2+)+S_(8)=NO`

Explanation

(Ion electron method)
i.
ii. iii. Blanance `O` atoms in eqauation(ii) by adding `2H_(2)O` to `RHS`
iv by adding `4H^(o+)` ions to `LHS`
`4H^(o+)+3e^(-)NO_(3)^(ө)rarrNO+2H_(2)O`
v. Multiply eqauiton (i) and `3` and equation (iv) by `16` and add them
`{:((24S^(2-)rarr3S_(8)+cancel48e^(-)),(64H^(o+)+cancel48e^(-)+16NO_(3)^(ө)rarr16NO+32H_(2)O):}/(24S^(2-)+64H^(o+)+16NO_(3)^(ө)rarr3S_(8)+16NO+32H_(2)O))/`
vi. `24CuS+64H^(o+)+16NO_(3)^(ө)rarr24Cu^(2)+3S_(8)+16NO+32H_(2)O`
Equation (vi) is the net redox requation.