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3KClO(3)+3H(2)SO(4)rarr3KHSO(4)+HClO(4)+...

`3KClO_(3)+3H_(2)SO_(4)rarr3KHSO_(4)+HClO_(4)+2ClO_(2)+H_(2)O`
Equivalent weight of `KClO_(3)` is

A

`(M)/(4)`

B

`(M)/(2)`

C

`(M+(M)/(2))`

D

`((M)/(4)+(M)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Disproportionation reaction
`ClO_(3)^(ө)rarrClO_(4)^(ө)+2e^(-)(x=2)` (oxidation)
`x-6= -1, x-8= -1`
`x=5 , x=7`
`e^(-)+ClO_(3)^(ө)rarrClO_(2), (x=1)` (reduction)
`x=5, x= -4= 0`
`x=4`
`Ew=M+(M)/(2)`
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