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The equivalent weight of H(2)SO(4) in th...

The equivalent weight of `H_(2)SO_(4)` in the following reaction is
`Na_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4)rarr3Na_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O`

A

`98`

B

`(98)/(6)`

C

`(98)/(2)`

D

`(98)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
B
In this reaction, `6mol` of `e^(-)` are involved with `1mol` if `H_(2)SO_(4)` in this redox reaction. `H_(2)SO_(4)` acts here as acidic medium.
`6e^(-)+Cr_(2)O_(7)^(-2)rarr2Cr^(3+)(x=6)`, (oxidation)
`2x-14= -2, 2x=6`
`2x=12`
`SO_(2)rarrSO_(4)^(2-)+2e^(-)]xx3(x=6)`
`x-4=0, x-8 = -2`
`x=4, x=6`
So, `Ew of H_(2)SO_(4)=(M)/(6)=(98)/(6)`
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The answer to each of the following questions is a single digit integer, ranging from 0 to 9. If the correct answers to the qustion numbers A,B,C and D (say) are 4,0,9 and 2 respectively, then the correct darkening of bubbles should be as shown on the side : The coefficient of H_(2)SO_(4) on balancing the equation K_(2)Cr_(2)O_(7) + H_(2)SO_(4) + KI rarrK_(2)SO_(4) + Cr_(2)(SO_(4))_(3) + H_(2)O+I_(2) is

Knowledge Check

  • The equivalent weight of H_(2)SO_(4) in the following reaction is Na_(2)Cr_(2)O_(7)+3SO_(2)+H_(2)SO_(4)=3Na_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O

    A
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    B
    `98/6`
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