Write balanced ionoic half equation (oxidation and reduction) for each of the following reactions:
(a) `Mn^(3+)(aq)rarrMnO_(2)(s)+Mn^(2+)(aq)`
(b) `Mn(s)+NO_(3)^(Ө)(aq) rarr Mn^(2+)(aq)+NO_(2)(g)`
(c ) `H_(2)O_(2)(aq) + Fe^(2+) (aq)rarrFe^(3+)(aq)+H_(2)O(l)`
(d) `Te(s)+NO_(3)^(Ө)(aq)rarr TeO_(2)(s)+NO(g)`

Answer

A

Explanation

a. `cancel(e^(-))+Mn^(3+)rarrMn^(2+)`
`x=3, x=2`
`2H_(2)O+Mn^(3+)rarrMnO_(2)+cancel(e^(-))+4H^(o+)`
`x=3, x-4=0`
`x=4`
`ulbar(2Mn^(3+)+2H_(2)OrarrMn^(2+)+MnO_(2)+4H^(o+))`
b. `MnrarrMn^(2+)cancel(2e^(-))`
`x=0, x=2`
`2H^(o+)+cancel(e^(-))+NO_(3)^(ө)rarrNO_(2)+H_(2)O]xx2`
`x-6= -1,x-4=0`
`x=5, x=4`
`ulbar(4H^(o+)+2NO_(3)^(ө)+MnrarrMn^(2+)+2NO_(2)+2H_(2)O)`
c. `F_(2)^(2+)rarrFe^(3+)+cancel(e)]xx2`
`2H+2cancel(e^(-))+H_(2)O_(2)rarr2H_(2)O`
`ulbar(2H^(o+)+2Fe^(2+)+H_(2)O_(2)rarr2Fe^(3+)+2H_(2)O)`
d. `4H^(o+)+3e^(-)+NO_(3)^(ө)rarrNO+2H_(2)O]xx4`
`x-6= -1, x-2=0`
`x=5, x=2`
`2H_(2)O+Terarr TeO_(2)+4cancel(e^(-))+4H^(o+)]xx3`
`x=0, x-4=0`
`x=4`
`ulbar(4H^(o+)+4NO_(3)^(ө)+3Terarr4NO+3TeO_(2)+2H_(2)O)`.