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Oxidation number of P in Ba(H(2)PO(2))(2...

Oxidation number of `P` in `Ba(H_(2)PO_(2))_(2)` is

A

`+3`

B

`+2`

C

`+1`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
A
`Ba^(2+)(H_(2)PO_(2))_(2)^(-1xx2)`
`:. H_(2)PO_(2)^(ө)=2+x-4= -1`
`:. X= +1`
Oxidation state of `P= +1`
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