Two acids A and B are titrated separately each time with 25 " mL of " `N-Na_(2)CO_(3)` solution to requrie 10 mL and 40 mL respectively, of their solution for complete neutralisation. What volume of A and B would you mix to produce 1 L of N-acid solution?

Explanation

`N_(A)=(25)/(10)=2.5N`
`N_(B)=(25)/(40)=0.625N`
Let V is the volume for solution of `N_(A)` and for the solution B volume is `(1-V)L`.
`therefore2.5V+0.625(1-V)=1` equivalent of acid
`thereforeV=0.2L`
`V_(A)=200mL,V_(B)=800mL`